The mean values for the radial distance for d | vedclass

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(B) In the formation of $PF_5$,phosphorus undergoes $sp^3d$ hybridization. During hybridization,the orbitals involved ($3s$,$3p$,and $3d$) undergo mix

Vedclass · Accepted Answer

$0.40 \ \mathring{A}$,$0.48 \ \mathring{A}$,$0.85 \ \mathring{A}$

Vedclass · Answer

(B) In the formation of $PF_5$,phosphorus undergoes $sp^3d$ hybridization. During hybridization,the orbitals involved ($3s$,$3p$,and $3d$) undergo mixing to form five equivalent $sp^3d$ hybrid orbitals. The $3d$ orbital,which is initially very diffuse (large radial distance of $2.4 \ \mathring{A}$),contracts significantly to participate in bonding with the electronegative fluorine atoms. The $3s$ and $3p$ orbitals remain relatively unchanged in their radial distribution compared to the $3d$ orbital. Therefore,the radial distances become approximately $0.40 \ \mathring{A}$,$0.48 \ \mathring{A}$,and $0.85 \ \mathring{A}$ respectively,reflecting the contraction of the $3d$ orbital.

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